Optimal. Leaf size=80 \[ -\frac {a \sqrt {1-a^2 x^2}}{20 x^4}-\frac {3}{40} a^5 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )-\frac {3 a^3 \sqrt {1-a^2 x^2}}{40 x^2}-\frac {\sin ^{-1}(a x)}{5 x^5} \]
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Rubi [A] time = 0.05, antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.625, Rules used = {4627, 266, 51, 63, 208} \[ -\frac {3 a^3 \sqrt {1-a^2 x^2}}{40 x^2}-\frac {a \sqrt {1-a^2 x^2}}{20 x^4}-\frac {3}{40} a^5 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )-\frac {\sin ^{-1}(a x)}{5 x^5} \]
Antiderivative was successfully verified.
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Rule 51
Rule 63
Rule 208
Rule 266
Rule 4627
Rubi steps
\begin {align*} \int \frac {\sin ^{-1}(a x)}{x^6} \, dx &=-\frac {\sin ^{-1}(a x)}{5 x^5}+\frac {1}{5} a \int \frac {1}{x^5 \sqrt {1-a^2 x^2}} \, dx\\ &=-\frac {\sin ^{-1}(a x)}{5 x^5}+\frac {1}{10} a \operatorname {Subst}\left (\int \frac {1}{x^3 \sqrt {1-a^2 x}} \, dx,x,x^2\right )\\ &=-\frac {a \sqrt {1-a^2 x^2}}{20 x^4}-\frac {\sin ^{-1}(a x)}{5 x^5}+\frac {1}{40} \left (3 a^3\right ) \operatorname {Subst}\left (\int \frac {1}{x^2 \sqrt {1-a^2 x}} \, dx,x,x^2\right )\\ &=-\frac {a \sqrt {1-a^2 x^2}}{20 x^4}-\frac {3 a^3 \sqrt {1-a^2 x^2}}{40 x^2}-\frac {\sin ^{-1}(a x)}{5 x^5}+\frac {1}{80} \left (3 a^5\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {1-a^2 x}} \, dx,x,x^2\right )\\ &=-\frac {a \sqrt {1-a^2 x^2}}{20 x^4}-\frac {3 a^3 \sqrt {1-a^2 x^2}}{40 x^2}-\frac {\sin ^{-1}(a x)}{5 x^5}-\frac {1}{40} \left (3 a^3\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {1}{a^2}-\frac {x^2}{a^2}} \, dx,x,\sqrt {1-a^2 x^2}\right )\\ &=-\frac {a \sqrt {1-a^2 x^2}}{20 x^4}-\frac {3 a^3 \sqrt {1-a^2 x^2}}{40 x^2}-\frac {\sin ^{-1}(a x)}{5 x^5}-\frac {3}{40} a^5 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )\\ \end {align*}
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Mathematica [C] time = 0.01, size = 51, normalized size = 0.64 \[ -\frac {1}{5} a^5 \sqrt {1-a^2 x^2} \, _2F_1\left (\frac {1}{2},3;\frac {3}{2};1-a^2 x^2\right )-\frac {\sin ^{-1}(a x)}{5 x^5} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.58, size = 85, normalized size = 1.06 \[ -\frac {3 \, a^{5} x^{5} \log \left (\sqrt {-a^{2} x^{2} + 1} + 1\right ) - 3 \, a^{5} x^{5} \log \left (\sqrt {-a^{2} x^{2} + 1} - 1\right ) + 2 \, {\left (3 \, a^{3} x^{3} + 2 \, a x\right )} \sqrt {-a^{2} x^{2} + 1} + 16 \, \arcsin \left (a x\right )}{80 \, x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.14, size = 101, normalized size = 1.26 \[ -\frac {3 \, a^{6} \log \left (\sqrt {-a^{2} x^{2} + 1} + 1\right ) - 3 \, a^{6} \log \left (-\sqrt {-a^{2} x^{2} + 1} + 1\right ) - \frac {2 \, {\left (3 \, {\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}} a^{6} - 5 \, \sqrt {-a^{2} x^{2} + 1} a^{6}\right )}}{a^{4} x^{4}}}{80 \, a} - \frac {\arcsin \left (a x\right )}{5 \, x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.00, size = 73, normalized size = 0.91 \[ a^{5} \left (-\frac {\arcsin \left (a x \right )}{5 a^{5} x^{5}}-\frac {\sqrt {-a^{2} x^{2}+1}}{20 a^{4} x^{4}}-\frac {3 \sqrt {-a^{2} x^{2}+1}}{40 a^{2} x^{2}}-\frac {3 \arctanh \left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{40}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.42, size = 82, normalized size = 1.02 \[ -\frac {1}{40} \, {\left (3 \, a^{4} \log \left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right ) + \frac {3 \, \sqrt {-a^{2} x^{2} + 1} a^{2}}{x^{2}} + \frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{x^{4}}\right )} a - \frac {\arcsin \left (a x\right )}{5 \, x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\mathrm {asin}\left (a\,x\right )}{x^6} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 4.23, size = 182, normalized size = 2.28 \[ \frac {a \left (\begin {cases} - \frac {3 a^{4} \operatorname {acosh}{\left (\frac {1}{a x} \right )}}{8} + \frac {3 a^{3}}{8 x \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {a}{8 x^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {1}{4 a x^{5} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\\frac {3 i a^{4} \operatorname {asin}{\left (\frac {1}{a x} \right )}}{8} - \frac {3 i a^{3}}{8 x \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i a}{8 x^{3} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i}{4 a x^{5} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} & \text {otherwise} \end {cases}\right )}{5} - \frac {\operatorname {asin}{\left (a x \right )}}{5 x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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